An electric motor with a winding resistance of 0.40 Ohm operates from a network with a voltage of 300 V at a current of 50 A

An electric motor with a winding resistance of 0.40 Ohm operates from a network with a voltage of 300 V at a current of 50 A Determine the amount of energy consumed in 5 hours, mechanical work and losses for heating the winding.

R = 0.4 ohm.

U = 300 V.

I = 50 A.

t = 5 h = 18000 s.

Q -?

W -?

A – ?

The amount of heat Q that is released in the winding is expressed by the formula of the Joule-Lenz law: Q = I ^ 2 * R * t, where I is the current in the motor winding, R is the resistance of the winding, t is the operating time of the motor.

Q = (50 A) ^ 2 * 0.4 Ohm * 18,000 s = 18,000,000 J.

The consumed electrical energy W is expressed by the formula of the Joule-Lenz law: W = I * U * t, where I is the current in the motor winding, U is the voltage, t is the operating time of the motor.

W = 50 A * 300 V * 18,000 s = 270,000,000 J.

A = W – Q.

A = 270,000,000 J – 18,000,000 J = 252,000,000 J.

Answer: Q = 18,000,000 J, W = 270,000,000 J, A = 252,000,000 J.