An electron flies into a uniform magnetic field with an induction of 0.045 T at a speed of 40,000 km / s

| September 1, 2021 | education

An electron flies into a uniform magnetic field with an induction of 0.045 T at a speed of 40,000 km / s, at an angle of 30 degrees to the lines of magnetic induction. Determine the force acting on a proton in a magnetic field.

It is known:

Homogeneous magnetic field;

Induction B = 0.045 T;

v = 40,000 km / s;

q = 1.6 * 10 ^ (- 19);

Angle A = 30 °;

Find F.

To calculate the force, we use the Lorentz force formulas.

F = q * v * B * sin a.

Substitute the known values into the formula and calculate the force.

F = 1.6 * 10 ^ (- 19) * 40,000 * 0.045 * sin 30 ° = 1.6 * 10 ^ (- 19) * 4 * 10 ^ 4 * 45 * 10 ^ (- 3) * 1/2 = 1.6 * 10 ^ (- 19) * 4 * 45 * 10 * 1/2 = 1.6 * 10 ^ (- 19) * 180 * 5 = 1.6 * 10 ^ (- 19) * 180 * 5 = 1440 * 10 ^ (- 19).

This means that the force acting on a proton in a magnetic field is equal to 1440 * 10: (- 19).



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