An electron moves in a vacuum at a speed of 3 ∙ 10 ^ 6 m / s in a uniform magnetic field perpendicular to the lines

An electron moves in a vacuum at a speed of 3 ∙ 10 ^ 6 m / s in a uniform magnetic field perpendicular to the lines of magnetic induction under the action of a force of 4.8 ∙ 10 ^ -14 N. Determine the induction of the magnetic field.

m = 9.1 * 10 ^ -31 kg.

q = 1.6 * 10 ^ -19 Cl.

V = 3 * 10 ^ -19 m / s.

Fl = 4.8 * 10 ^ -14 N.

∠α = 90 “.

B -?

A moving charge in a magnetic field is affected by the Lorentz force Fl, the value of which is determined by the formula: Fl = q * B * V * sinα, where q is the magnitude of the charge, B is the magnetic induction of the field, V is the velocity of the charge, ∠α is the angle between the magnetic induction B and speed V.

Since V and B are mutually perpendicular, then sin90 “= 1.

The formula for determining the magnetic induction B will take the form: B = Fl / q * V.

B = 4.8 * 10 ^ -14 N / 1.6 * 10 ^ -19 C * 3 * 10 ^ -19 m / s = 1 * 10 ^ 24 T.

Answer: the magnetic induction of the field is B = 1 * 10 ^ 24 T.