An equilateral triangle is inscribed with a circle with a radius of 6 cm, OB = 10 cm. Find its side BC.

1.AB = BC = AC;
2. We write the equality above as a, then the radius of the inscribed circle in an equilateral triangle can be written as follows:
r = a / 2√3;
a = 2√3;
thus we knew by hypothesis that r = 6.
3.a = 2√3 * 6;
a = 12√3.
Answer: a = 12√3.



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