An excess of barium chloride solution is added to 200 g of a 2% sulfuric acid solution.

An excess of barium chloride solution is added to 200 g of a 2% sulfuric acid solution. Calculate the mass of the precipitate formed.

1. We make a chemical equation, not forgetting to put down the coefficients:

H2SO4 + BaCl2 = BaSO42HCl.

2. Let’s find the mass of sulfuric acid:

m = 0.02 * 200 = 4g.

3. Find the amount of substance H2SO4:

n (H2SO4) = 4/98 = 0.4 mol.

4. From the equation you can see:

n (H2SO4) = n (BaSO4).

5. Find the mass of BaSO4:

m (BaSO4) = 0.4 * 137 = 54.8g.

Answer: m (BaSO4) = 54.8g.