An excess of barium chloride solution was added to 120 g of a 60% potassium carbonate solution.

An excess of barium chloride solution was added to 120 g of a 60% potassium carbonate solution. what is the mass of the sediment formed?

1. Let’s write down the reaction equation:

K2CO3 + BaCl2 = 2KCl + BaCO3.

2. Find the amount of potassium carbonate:

m (K2CO3) = m (solution) * ω (K2CO3) / 100% = 120 g * 60% / 100% = 72 g.

n (K2CO3) = m (K2CO3) / M (K2CO3) = 72 g / 138 g / mol = 0.52 mol.

3. Using the reaction equation, we find the amount, and then the mass of barium carbonate:

n (BaCO3) = n (K2CO3) = 0.52 mol.

m (BaCO3) = n (BaCO3) * M (BaCO3) = 0.52 mol * 197 g / mol = 102.8 g.

Answer: m (BaCO3) = 102.8 g.