An excess of barium chloride was added to a solution of sulfuric acid weighing 120 g with a mass

An excess of barium chloride was added to a solution of sulfuric acid weighing 120 g with a mass fraction of acid of 6%. Calculate the mass of the resulting sediment.

Barium chloride reacts with sulfuric acid. This results in the formation of water-insoluble barium sulfate, which precipitates. This reaction is described by the following chemical equation.

BaCl2 + H2SO4 = BaSO4 + 2HCl;

Barium chloride reacts with sulfuric acid in equivalent molar amounts. This produces the same amount of insoluble salt.

Let’s determine the chemical amount of sulfuric acid.

M H2SO4 = 2 + 32 + 16 x 4 = 98 grams / mol; N H2SO4 = 120 x 0.06 / 98 = 0.0735 mol;

Barium sulfate will be obtained in the same molar amount.

Let’s calculate its weight.

M BaSO4 = 137 + 32 + 16 x 4 = 233 grams / mol; m BaSO4 = 0.0735 x 233 = 17.125 grams;