An excess of calcium was added to the nitrogen released during the decomposition of 57.6 g of ammonium nitrite.

An excess of calcium was added to the nitrogen released during the decomposition of 57.6 g of ammonium nitrite. Calculate the mass of the substance resulting from the reaction.

Given:
m (NH4NO2) = 57.6 g;
Ca
Find: m (Ca3N2) -?
Decision:
n = m / M
M (NH4NO2) = 14 + 4×1 + 14 + 2×16 = 64 g / mol
n (NH4NO2) = 57.6 g / 64 g / mol = 0.9 mol
According to the reaction equation, using the proportion, you can calculate the amount of nitrogen that is released:
0.9 mol x mol
NH4NO2 = N2 + 2H2O
1 mol 1 mol
x = 0.9 mol (N2)
Using the equation of the reaction of interaction with an excess of calcium, in the same way we find the amount of the substance obtained:
0.9 mol y mol
3Ca (g) + N2 = Ca3N2
1 mol 1 mol
y = 0.9 mol
m = n x M
M (Ca3N2) = 3×40 + 2×14 = 148 g / mol
m (Ca3N2) = 0.9 mol х 148 g / mol – 133.2 g