An excess of copper (II) chloride solution was added to 50 g of an 8% sodium hydroxide

| September 9, 2021 | education

An excess of copper (II) chloride solution was added to 50 g of an 8% sodium hydroxide solution. Determine the mass of the precipitated sediment.

We draw up an equation for the reaction and place the coefficients:
2NaOH + CuCl2 = 2NaCl + Cu (OH) 2.
The precipitate is copper hydroxide. The mass of this substance must be found.
1) From the formula for calculating the mass fraction of a substance, we express the mass of the solute and find it for sodium hydroxide: 50 * 8/100 = 4g.
2) Find the amount of sodium hydroxide substance. To do this, divide the mass of sodium hydroxide by its molar mass: 4 / (23 + 16 + 1) = 4/40 = 0.1 mol.
3) According to the reaction equation, there is 2 mol of sodium hydroxide for one mole of copper hydroxide. This means that the amount of sediment substance is: 2 * 0.1 = 0.2 mol.
4) Find the mass of the sediment: 0.2 * 98 = 19.6 g – the answer.



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