An excess of dilute sulfate acid solution was added to 112 g of iron filings. Find the volume of gas that will

An excess of dilute sulfate acid solution was added to 112 g of iron filings. Find the volume of gas that will evolve and the mass (in grams) of the salt in the final solution.

Let’s implement the solution:

Let’s make the equation:
Fe + H2SO4 = FeSO4 + H2 – substitutions, ferrous sulfate, hydrogen is released;

Calculations:
M (Fe) = 55.8 g / mol.

M (FeSO4) = 151.8 g / mol.

M (H2) = 2 g / mol.

Determine the amount of the original substance, if the mass is known:
Y (Fe) = m / M = 112 / 55.8 = 2 mol;

Y (FeSO4) = 2 mol, Y (H2) = 2 mol since the amount of substances according to the equation is 1 mol.

Find the mass of the product:

m (FeSO4) = Y * M = 2151.8 = 303.6 g.

Product volume:

V (H2) = 2 * 22.4 = 44.8 liters.

Answer: the mass of ferrous sulfate is 303.6 g, the volume of hydrogen is 44.8 liters.