An excess of hydrochloric acid solution was added to 1000 g of a 3.4% silver nitrate solution. Determine the mass of the sediment formed.
1. Let’s write down the reaction equation:
AgNO3 + HCl = AgCl + HNO3.
2. Find the amount of silver nitrate:
m (AgNO3) = m (solution) * ω (AgNO3) / 100% = 1000 g * 3.4% / 100% = 34 g.
n (AgNO3) = m (AgNO3) / M (AgNO3) = 34 g / 170 g / mol = 0.2 mol.
3. According to the reaction equation, we find the amount of silver chloride, and then its mass:
n (AgCl) = n (AgNO3) = 0.2 mol.
m (AgCl) = n (AgCl) * M (AgCl) = 0.2 mol * 143.5 g / mol = 28.7 g.
Answer: m (AgCl) = 28.7 g.
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