An excess of potassium sulfide was added to 63.5 g of a solution with a mass fraction of iron (II)

| July 3, 2021 | education

An excess of potassium sulfide was added to 63.5 g of a solution with a mass fraction of iron (II) chloride of 6%. Determine the mass of the precipitated sediment.

We draw up the reaction equation and place the coefficients: 2FeCl3 + 3K2S = Fe2S3 + 6KCl.
1) Calculate the mass of the solute of ferric chloride in its 6% solution. To do this, we multiply the mass of the solution by the mass fraction of the substance and divide by one hundred percent: 63.5 * 5/100 = 3.18g.
2) Find the amount of ferric chloride substance. To do this, we divide the mass by the molar mass: 3.18 / 162 = 0.02 mol.
3) According to the reaction equation, there are two moles of iron chloride for one mole of iron sulfide. This means that the amount of sediment substance is 0.01 mol.
4) Sludge weight: 0.01 * 208 = 2.08g – answer.



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.