An excess of silver nitrate solution was added to 200 g of a 12.25% sulfuric acid solution.

An excess of silver nitrate solution was added to 200 g of a 12.25% sulfuric acid solution. Determine the mass of the precipitated sediment.

Reaction equation: H2SO4 + 2AgNO3 = 2HNO3 + Ag2SO4
Let’s find the mass of the sulfuric acid substance: m in-va = w * m solution = 0.1225 * 200 g = 24.5 g. Let’s find the amount of sulfuric acid substance n = m / M = 24.5 g / 98 g / mol = 0.25 mol. (M – molar mass, determined by the periodic table). The precipitate is silver sulfate Ag2SO4. According to the reaction, 1 mol of precipitate is formed from 1 mol of sulfuric acid, which means n (H2SO4) = n (Ag2SO4) = 0.25 mol. Let us find the mass of the sediment: m = n * M = 0.25 mol * 312 g / mol = 78 g.
Answer: m (Ag2SO4) 78 g.