An excess of soda is added to a solution containing 0.5 mol of CaCL2. Calculate the mass of the precipitate.
| December 12, 2020 | education
Na2CO3 + CaCl2 = 2NaCl + CaCO3 (white precipitate)
According to the condition n (CaCl2) = 0.5 mol, we find n (CaCO3) =?
1 mol – 1 mol
0.5 mol – x mol
x = 0.5 mol,
n (CaCO3) = 0.5 mol.
Now we find m (CaCO3) =?
m (CaCO3) = M (CaCO3) * n (CaCO3) = 100g \ mol * 0.5mol = 50g.
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