An excess of sulfuric acid solution was added to 70 g of a solution of barium chloride with a mass fraction

An excess of sulfuric acid solution was added to 70 g of a solution of barium chloride with a mass fraction of a solute of 2.5%. Calculate the mass of the sulfuric acid.

Let us write the equation for the reaction of barium chloride with an excess of sulfuric acid.

BaCl2 + H2SO4 = BaSO4 + 2HCl

Since the mass of a 2.5% barium chloride solution (70 g) is known, the mass of barium chloride can be found.

m (BaCl2) = 70 * 2.5 / 100 = 1.75 g

To find the mass of the reacted sulfuric acid, we calculate the amount of molar barium chloride reacted.

n (BaCl2) = m (BaCl2) / M (BaCl2) = 1.75 / 208.2 = 0.0084 mol

n (BaCl2) = n (H2SO4) = 0.0084 mol

Knowing the number of moles of acid, we find the mass:

m (H2SO4) = n (H2SO4) * M (H2SO4) = 0.0084 * 98.08 = 0.82 g.