An excess of sulfuric acid solution was added to a 1 kg solution with a mass fraction of barium

An excess of sulfuric acid solution was added to a 1 kg solution with a mass fraction of barium chloride of 6.24%. Determine the mass of the salt formed.

Barium chloride reacts with sulfuric acid. This results in the formation of water-insoluble barium sulfate, which precipitates. This reaction is described by the following chemical equation.

BaCl2 + H2SO4 = BaSO4 + 2HCl;

Barium chloride reacts with sulfuric acid in equivalent molar amounts. At the same time, an equal amount of insoluble salt is synthesized.

Determine the chemical amount of barium chloride.

M BaCl2 = 137 + 35.5 x 2 = 208 grams / mol; N BaCl2 = 1000 x 0.0624 / 208 = 0.3 mol;

The same amount of barium sulfate will be synthesized.

Let’s calculate its weight.

M BaSO4 = 137 + 32 + 16 x 4 = 233 grams / mol; m BaSO4 = 0.3 x 233 = 69.9 grams;