An excess of sulfuric acid was added to 1.62 g of zinc oxide. The amount of salt formed is?
| May 25, 2021 | education
The equation for the reaction of zinc oxide with sulfuric acid:
ZnO + H2SO4 = Zn SO4 + H2O.
The molar mass of zinc oxide: M (ZnO) = (65 + 16) = 81 g / mol.
The mass of zinc oxide 1.62 g corresponds to the amount of the substance: 1.62 / 81 = 0.02 mol.
From the reaction equation, it can be seen that 1 mole of zinc sulfate is formed from 1 mole of zinc oxide, which means that 0.02 mole of zinc sulfate was obtained as a result of the reaction.
The molar mass of zinc sulfate: M (ZnSO4) = (65 + 32 + 16 × 4) = 161 g / mol.
Zinc sulfate mass: 161 × 0.02 = 3.22 g.
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