An excess of zinc sulfate solution was added to 60% g of a 10% barium chloride solution.

An excess of zinc sulfate solution was added to 60% g of a 10% barium chloride solution. Calculate the mass of the precipitate formed.

Given:

m (BaCl2) = 60 g

w% (BaCl2) = 10%

To find:

m (salt) -?

Decision:

BaCl2 + ZnSO4 = BaSO4 + ZnCl2, – we solve the problem, relying on the composed reaction equation:

1) Find the mass of barium chloride in solution:

m (BaCl2) = 60 g * 0.1 = 6 g

2) Find the amount of barium chloride:

n (BaCl2) = m: M = 6 g: 208 g / mol = 0.029 mol

3) We compose a logical expression:

if 1 mol of BaCl2 gives 1 mol of BaSO4,

then 0.029 mol of BaCl2 will give x mol of BaSO4,

then x = 0.029 mol.

4) Find the mass of barium sulfate precipitated:

m (BaSO4) = n * M = 0.029 mol * 233 g / mol = 6.7 g.

Answer: m (BaSO4) = 6.7 g.