An expanded clay block measuring 41 x 20 x 20 cm was submerged in water. Find the change in its weight.

a = 41 cm = 0.41 m.
b = 20 cm = 0.2 m.
d = 20 cm = 0.2 m.
ρ = 1000 kg / m ^ 3.
g = 9.8 m / s ^ 2.
ΔР -?
ΔР = Farch.
The buoyancy force of Archimedes is determined by the formula: Farch = ρ * g * V. Where ρ is the density of the liquid in which the body is immersed, g is the acceleration of gravity, V is the volume of the immersed part of the body in the liquid.
V = a * b * d.
ΔР = ρ * g * a * b * d.
ΔP = 1000 kg / m ^ 3 * 9.8 m / s ^ 2 * 0.41 m * 0.2 m * 0.2 m = 160.72 N.
Answer: ΔР = 160.72 N.



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