An ice floe floats in the sea, part of which is above the water. Its volume is 196 m ^ 3. Determine the volume

An ice floe floats in the sea, part of which is above the water. Its volume is 196 m ^ 3. Determine the volume of the underwater part. The density of ice is 900kg / m ^ 3, the density of water is 1.04 * 10 ^ 3 kg / m ^ 3

First, we determine the mass ml of the ice floe by multiplying the ice density by the volume of the ice floe:

ml = 900 * 196 = 176400 kg.

According to Archimedes’ law, the mass mw of water in the desired volume Vp of the underwater part of the ice floe should be equal to the mass ml. Therefore, the volume Vp is equal to the mass ml divided by the density of water:

Vp = 176400 / (1.04 * 10 ^ 3) = 169.6 m3.

Answer: 169.6 m3.