An icebreaker with a mass of 5000 tons, moving by inertia at a speed of 10 m / s, collides with a stationary ice floe
| May 9, 2021 | education
An icebreaker with a mass of 5000 tons, moving by inertia at a speed of 10 m / s, collides with a stationary ice floe, while its speed drops by 2 m / s. Determine the mass of the ice floe, disregard the resistance.
Initial data: m1 (icebreaker weight) = 5000 t (5000 * 10 ^ 3 kg); V1 (speed of the icebreaker before colliding with the ice floe) = 10 m / s; V2 (ice floe speed) = 0 m / s; ΔV (change in icebreaker speed after collision) = 2 m / s.
We express the mass of the ice floe from the formula (we use the law of conservation of momentum): m1 * V1 = (m1 + m2) * (V1 – ΔV), whence m2 = m1 * V1 / (V1 – ΔV) – m1.
Calculation: m2 = 5000 * 10 ^ 3 * 10 / (10 – 2) – 5000 * 10 ^ 3 = 1 250 000 (1250 t).
Answer: The mass of the ice floe is 1250 tons.
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