An ideal heat engine, having received 4 kJ of heat from a heater at a temperature of 127 C, performed work of 800 J.

An ideal heat engine, having received 4 kJ of heat from a heater at a temperature of 127 C, performed work of 800 J. Determine the temperature of the refrigerator.

Initial data: Q (amount of heat received by the heat engine) = 4 kJ (4000 J); Тн (heater temperature) = 400 К (127 ºС); A (work done by the engine) = 800 J.
The temperature of the refrigerator of an ideal heat engine is determined from the equality: A / Q = η = 1 – Тх / Тн, whence Тх / Тн = 1 – A / Q and Тх = (1 – A / Q) * Тн.
Calculation: Тх = (1 – 800/4000) * 400 = 320 K (47 ºС).
Answer: The temperature of the refrigerator is 320 K.