An ingot of a silver-zinc alloy weighing 3.5 kg contained 76% silver. It was alloyed with another ingot and obtained

| June 24, 2021 | education

An ingot of a silver-zinc alloy weighing 3.5 kg contained 76% silver. It was alloyed with another ingot and obtained an ingot weighing 10.5 kg, the silver content of which is 84%. How much silver was in the second bar?

Find the silver content of alloy number one.

In the initial data for this task, it is reported that this alloy of silver with zinc weighing three and a half kilograms contains 76% silver, therefore, the mass of silver in this alloy is (76/100) * 3.5 = 0.76 * 3.5 = 2.66 kg.

Let’s find the silver content in the resulting alloy.

According to the condition of the problem, this alloy of silver with zinc weighing ten and a half kilograms contains 84% ​​silver, therefore, the mass of silver in this alloy is (84/100) * 10.5 = 0.84 * 10.5 = 8.82 kg.

Therefore, the mass of silver in ingot number two is 8.82 – 2.66 = 6.16 kg, the mass of the entire ingot is 10.5 – 3.5 = 7 kg, and the silver content is:

100 * 6.16 / 7 = 616/7 = 88%.

Answer: 88%.



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