An ingot of silver weighing 120 g, while cooling from 66 s to 16 s, transferred 1.5 kJ of heat to the environment.

An ingot of silver weighing 120 g, while cooling from 66 s to 16 s, transferred 1.5 kJ of heat to the environment. What is the specific heat of silver?

Initial formula: Q = m × c × (t1-t2)
We derive the specific heat from the formula: c = Q ÷ (m × (t1-t2))
We translate all these values into SI (international system):
m = 120g = 0.12kg
Q = 1.5kJ = 1500J
We substitute these values into the formula and we get the equation: s = 1500 ÷ (0.12 × (66-16) = 250 J / kg × K
Answer: c = 250 J / kg × K



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