An iron ball floats in mercury. What part of its volume is immersed in liquid?
| January 27, 2021 | education
Data: ρrt (density of mercury) = 13600 kg / m3; ρzh (density of iron) = 7800 kg / m3.
The volume of the submerged part of the taken iron ball: Fa = Fт and ρрт * g * Vп = ρl * V * g, whence we express: Vп / V = ρl * g / (ρрт * g) = ρl / ρрт = 7800/13600 = 0.574 or 57.4%.
Answer: 57.4% of the taken iron ball is immersed in mercury.
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