An iron bar taken at a temperature of 500 degrees Celsius is thrown into a snowdrift at 0 degrees Celsius

An iron bar taken at a temperature of 500 degrees Celsius is thrown into a snowdrift at 0 degrees Celsius, cooling the bar melted 2 kg of snow. What is the mass of the bar?

tb = 500 ° C.

tс = 0 ° C.

Сж = 460 J / kg * ° C.

q = 3.4 * 10 ^ 5 J / kg.

msn = 2 kg.

mb -?

When an iron bar gets into the snow, its temperature will decrease to the temperature of the snow. In this case, an amount of heat will be released, which will go to melting the ice.

Szh * mb * (tb – tc) = q * msn – heat balance equation.

Сж is the specific heat of iron, q is the specific heat of melting of ice, the value of which is taken from the corresponding tables.

mb = q * msn / Szh * (tb – tc).

mb = 3.4 * 10 ^ 5 J / kg * 2 kg / 460 J / kg * ° C * (500 ° C – 0 ° C) = 2.96 kg.

Answer: an iron block weighing mb = 2.96 kg was thrown into the snow.