An iron bar taken at a temperature of 500 degrees Celsius is thrown into a snowdrift at 0

An iron bar taken at a temperature of 500 degrees Celsius is thrown into a snowdrift at 0 degrees Celsius, cooling the bar melted 2 kg of snow. What is the mass of the bar?

Given:
t1 = 500 C
t2 = 0 C
c = 460 J / kg * C – specific heat of iron
m2 = 2 kg – snow mass
L = 330 kJ / kg = 330,000 J / kg – specific heat of melting of snow
m1 -?
Q1 = L * m2 – the amount of heat required to melt snow
Q2 = – с * m1 * (t1-t2) – the amount of heat required to cool the snow
we use the heat balance equation: Q1 = – Q2
c * m1 * (t1 – t2) = L * m2
m1 = L * m2 / c * (t1 – t2)
m1 = 330,000 * 2/460 * (500 – 0) = 660,000 / 230,000 = 2.9 kg \
Answer: m1 = 2.9 kg