An iron bar weighing 7.8 kg is immersed in a vessel with water with a cross-sectional area S = 50 cm2.

An iron bar weighing 7.8 kg is immersed in a vessel with water with a cross-sectional area S = 50 cm2. How much will the water level in the vessel rise? No water is poured out.

To find out the change in the water level in the vessel, consider the formula: Δh = ΔV / Sс = mb / (ρl * Sс), where mb is the mass of an iron bar immersed in the vessel (mb = 7.8 kg); ρzh – density of iron (const; ρzh = 7800 kg / m3); Sс – cross-sectional area of the used vessel (Sс = 50 cm2 = 5 * 10 ^ -3 m2).

Let’s perform the calculation:: Δh = mb / (ρl * Sc) = 7.8 / (7800 * 5 * 10 ^ -3) = 0.2 m.

Answer: The water level in the vessel used should rise by 0.2 m.