An iron beam 10 meters long and weighing 500 kg lies on the ground. How much force must be applied to lift it at one end.
These tasks: m (mass of the considered iron beam) = 10 m; m (beam weight) = 500 kg.
Reference values: g (acceleration due to gravity) ≈ 10 m / s2.
The force applied to the end of the beam under consideration can be expressed from the equality: F * l = ΔEp = m * g * h = m * g * l / 2, whence F = m * g / 2.
Let’s perform the calculation: F = 500 * 10/2 = 2.5 * 10 ^ 3 N (2.5 kN).
Answer: A force of 2.5 kN is required to be applied to the beam in question.
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