An iron beam 10 meters long and weighing 500 kg lies on the ground. How much force must

An iron beam 10 meters long and weighing 500 kg lies on the ground. How much force must be applied to lift it at one end.

These tasks: m (mass of the considered iron beam) = 10 m; m (beam weight) = 500 kg.

Reference values: g (acceleration due to gravity) ≈ 10 m / s2.

The force applied to the end of the beam under consideration can be expressed from the equality: F * l = ΔEp = m * g * h = m * g * l / 2, whence F = m * g / 2.

Let’s perform the calculation: F = 500 * 10/2 = 2.5 * 10 ^ 3 N (2.5 kN).

Answer: A force of 2.5 kN is required to be applied to the beam in question.