An iron beam 5 m long and 450 kg in weight lies on the ground. What force should be applied to lift it at one end?
| December 14, 2020 | education
Given:
l-5m
m-450kg
g = 9.8
Find: F-?
Decision:
Fl = mg * 1/2
F = mg: 2 = (450 * 9.8): 2 = 2205H
Answer: a force must be applied equal to 2205 N in order to raise the iron beam at one end
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