An iron meteorite weighing 80 kg at a temperature of 39 ° C flies into the atmosphere at a speed of 1400 m / s.

An iron meteorite weighing 80 kg at a temperature of 39 ° C flies into the atmosphere at a speed of 1400 m / s. Considering that 80% of its kinetic energy is spent on heating and melting a meteorite, it is a determinant of what mass of a meteorite will melt. The melting point of iron is 1539 ° C, the specific heat of fusion of iron is 270 kJ / kg.

Given: m (mass) = 80 kg; t0 (initial temp.) = 39 ºС; V (velocity when entering the atmosphere) = 1400 m / s; η (process efficiency) = 80% (0.8).

Constants: Czh (specific heat capacity of iron) = 1539 ºС; λ (beats heat of fusion) = 270 kJ / kg (270 * 10 ^ 3 J / kg); tmelt (melting point) = 1539 ºС.

Let us express the mass of the melted part of the meteorite: η * m * V ^ 2/2 = Сж * m * (tmelt – t0) + λ * mх; mх = (η * m * V ^ 2/2 – Сж * m * (tpl – t0)) / λ.

Calculation: mх = (0.8 * 80 * 1400 ^ 2/2 – 460 * 80 * (1539 – 39)) / (270 * 10 ^ 3) = 27.85 kg.



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