An iron plate weighing 5.2 g was kept for a long time in a solution containing 1.6 g of CuSO4. At the end of the reaction

An iron plate weighing 5.2 g was kept for a long time in a solution containing 1.6 g of CuSO4. At the end of the reaction, the plate was removed from the solution and dried. What was its mass equal to.

1) Let’s compose the reaction equation: CuSO4 + Fe ==> Cu + FeSO4
2) Determine the mass of the plate in the reaction: m (Fe) = 1.6 * 56/160 = 0.56 g
3) Determine the mass of the plate after the reaction: m (Fe after p-tion) = 5.2-0.56 = 4.64 g
Answer: m (Fe after solution) = 4.64 g