An iron slab measuring 3.8×0.5×0.32 is submerged in water at half its volume

An iron slab measuring 3.8×0.5×0.32 is submerged in water at half its volume to find the Archimedean force acting on the plate without a condition.

ρw = 1000 kg / m3.

a = 3.8 m.

b = 0.5 m.

h = 0.32 m.

g = 10 m / s2.

Vv = V / 2.

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Since part of the iron plate is in the water, the buoyancy force of Archimedes Farch acts on it, directed vertically upwards.

The buoyancy force of Archimedes Farch is expressed by the formula: Farch = ρw * g * Vw, where ρw is the density of the liquid in which the plate is immersed, g is the acceleration of gravity, Vw is the volume of the plate, which is in the water.

Since the iron plate has the shape of a rectangular parallelepiped, therefore, its volume V is expressed by the formula: V = a * b * h, where a is the length, b is the width, and h is the height of the iron plate.

Since half the volume of the slab is in the water, then Vw = V / 2 = a * b * h / 2.

The buoyancy force of Archimedes Farch, will be determined by the formula: Farch = a * b * h * ρw * g / 2.

Farch = 3.8 m * 0.5 m * 0.32 m * 1000 kg / m3 * 10 m / s2 / 2 = 3040 N.

Answer: the buoyancy force of Archimedes Farch = 3040 N. acts on an iron plate in water.