An iron weight weighing 5 kg cools from 1127 ° C to 327 ° C. How much lead, taken at a temperature of 27 ° C

An iron weight weighing 5 kg cools from 1127 ° C to 327 ° C. How much lead, taken at a temperature of 27 ° C, can be melted due to the heat released when the iron weight cools?

Given:
m (iron weight) = 5kg
t (initial) = 1128 ° С
t (final) = 327 ° С
c (glands) = 460J / (kg * ° C)
t (floating lead) = 327 ° С
λ (lead) = 24000 J / kg
Find: m (lead) = ???
Decision:
t (final) = t (floating lead)
Q = cm (t (start) -t (end))
Q = 5kg * 460J / (kg * ° С) * (1128 ° С-327 ° С)
Q = 1842300 J
Q = λm:
1842300 J = 24000 J / kg * m (lead)
m (lead) = 1842300 J / 24000 J / kg
m (lead) = 76.8 kg
Answer: 76.8 kg