An isosceles triangle ABC with base BC is inscribed in a circle. Find the angles of a triangle if the arc is BC = 102 degrees
Given: ΔABC – isosceles inscribed in a circle.
AB = AC.
BC = 102 °.
∠A -? ∠B -? ∠C -?
Let us find the angle at the vertex of an isosceles triangle as half the degree measure of the arc:
∠A = 1/2 * 102 ° = 51 °.
Find two equal angles at the base of an isosceles triangle.
∠В = ∠С = 1/2 (180 ° – 51 °) = 129/2 = 64 ° 30 ‘.
Answer: 51 °; 64 ° 30 ‘; 64 ° 30 ‘.
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