An observer located at a distance of 2.2 km from the sound source hears the sound that came through

An observer located at a distance of 2.2 km from the sound source hears the sound that came through the air 5 seconds later than the sound from the same source that came through the water. Determine the speed of sound in water from these data, if the speed of sound in air is 340 m / s

Velocity V (uniform), time T and distance S are related by the relationship V = S / t or t = S / V.
The difference in the sound travel time can be written in the form
TV air – T in water = S / V in air. – S / V in water
Or numerically
5 s = 2200 m / 340 m / s – 2200 m / V in water
5s = 6.47 s – 2200 m / V in water
2200 m / V in water = 1.47 s
V in water = 2200 m / 1.47 s = 1496.6 m / s
Answer: 1496 m / s



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