An unknown alkene weighing 2.8 g interacts with the required amount of hydrogen bromide to form 6.85 g

An unknown alkene weighing 2.8 g interacts with the required amount of hydrogen bromide to form 6.85 g of the reaction product. Determine the molecular formula of the alkene.

The solution of the problem:
2.8 g 2.24 L CnH2n + H2 = CnH2nMr 22.4 L 2.8 / Mr = 2.24 / 22.4Mr (CnH2n) = 2.8 * 22.4 / 2.24 = 2812n + 2n = 2814n = 28n = 2 C2H4-ethene



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