Analysis of one of the nitrogen oxides showed that the mass fractions of nitrogen and oxygen

Analysis of one of the nitrogen oxides showed that the mass fractions of nitrogen and oxygen in it are equal to 36.84 and 63.16%, respectively. Determine the simplest formula of the oxide

First of all, let us denote the mass of nitrogen and oxygen atoms in the formula through x and y. From the periodic table, the atomic masses of these elements are equal to 14 and 16. And it turns out that in this compound there will be such a proportion.

14 x: 16 y

And according to the problem statement, this ratio is 36.84: 63.16.

And from here follows.

14 x: 16 y = 36.84: 63.16

And we get that x: y = (36.84: 14): (63.16: 16) = 2.63: 3.9475 = 1: 1.5 = 2: 3 (we get this after multiplying by two, since the formula should contain smallest integers).

So this is the formula.

N2O3 or nitric oxide.



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