Analyzing crossing shows that one of the parents forms the following types of gametes: PB (42.4%)

| July 11, 2021 | education

Analyzing crossing shows that one of the parents forms the following types of gametes: PB (42.4%), Pb (6.9%), pB (7.0%), pb (43.7%). List all the genetic conclusions that can be drawn from this result; write the genotypes of the parents and all offspring; determine the distance between genes.

Based on the results obtained, the following conclusions can be drawn:

1) The genes responsible for the manifestation of P and B traits are on the same chromosome and are inherited linked: P is linked to B, p is linked to b.

2) A small proportion of Pb and pB gametes indicates that crossing over occurs between homologous chromosomes, its probability is 7% (by the number of these gametes).

3) The distance between genes is equal to the percentage of crossing over, i.e. 7 morganid.

4) When analyzing crosses, one individual is homozygous for the recessive trait (ppbb). According to the gametes formed by the second parent, it can be concluded that he is diheterozygous.

Parents: PpBb x ppbb,

Gametes: PB, pb, Pb, pB x pb,

Offspring: PpBb (probability 42.4%), ppbb (probability 43.7%), Ppbb (probability 6.9%), ppBb (probability 7%).



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