Analyzing the iron alloy for carbon content, 1 g of the alloy was burned in the laboratory. In this case, 112 ml of carbon (IV)

Analyzing the iron alloy for carbon content, 1 g of the alloy was burned in the laboratory. In this case, 112 ml of carbon (IV) oxide were seen. Calculate the mass fraction of carbon in this alloy. Name the alloy.

C + O2-> CO2. V (CO2) = 112 ml = 0.112 liters, n (CO2) = V / Vmol = 0.112 / 22.4 = 0.005 mol = n (C), m (C) = n * M = 0.005 * 12 = 0.06 gram, w (C) = m (C) * 100% / m (alloy) = 0.06 * 100.1 = 6%, Fe3C (iron carbide or most likely cast iron) is most suitable, since in Fe3C w (C) = 6.67%.
Answer: w (C) = 6%, cast iron.