And a car weighing 1.5 tons moves uphill with an acceleration of 0.3 meters per second.

And a car weighing 1.5 tons moves uphill with an acceleration of 0.3 meters per second. Find the force of gravity if the slope of the mountain is 0.03.

m = 1.5 t = 1500 kg.

g = 10 m / s2.

a = 0.3 m / s2.

h / S = sinα = 0.03.

F -?

Fт -?

The force of gravity F is the force with which the earth attracts all objects that are on its surface, due to gravitational attraction. The force of gravity is always directed vertically downward and is determined by the formula: F = m * g, where m is the mass of the car, g is the acceleration of gravity.

F = 1500 kg * 10 m / s2 = 15000 N.

For the movement of a car on an inclined plane Let us write 2 Newton’s law in vector form: m * a = Ft + m * g + N, where Ft is the thrust force of the car engine, m * g is the force of gravity, N is the reaction force of the surface of the inclined plane.

ОХ: m * a = Fт – m * g * sinα.

OU: 0 = – m * g * cosα + N.

Fт = m * a + m * g * sinα = m * (a + g * sinα).

Ft = 1500 kg * (0.3 m / s2 + 0.03 * 10 m / s2) = 900 N.

Answer: the gravity of the car is F = 15000 N, when driving on an inclined plane, the traction force of the car engine is Ft = 900 N.