Angle 2 = 120 degrees, Angle 1 = 60 degrees, Angle 3 is 38 degrees greater than Angle 5. Find Angle 3, Angle 4, Angle 5

Angle ∠6 and ∠2 are adjacent angles, the sum of which is 180, then ∠6 = 180 – ∠2 = 180 – 120 = 60.

Angle ∠7 is adjacent to angle 2, the sum of which is 180, then ∠7 = 180 – ∠1 = 180 – 60 = 120.

Angle ∠7 = ∠2, angle ∠6 = ∠1, and since these are the corresponding angles at the intersection of straight lines a and in secant c, straight lines a and b are parallel.

Then the angle ∠3 = ∠8, and their sum ∠3 + ∠8 = 180.

Angle ∠8 = ∠5.

Let the angle ∠8 = X0, then the angle ∠3 = (X + 38).

X + X + 38 = 18.

2 * X = 180 – 38 = 142.

X = 142/2 = 71.

Angle ∠5 = 71.

Angle ∠3 = 71 + 38 = 109.

Angle ∠4 = ∠5 as vertical angles.

Answer: ∠3 = 109, ∠4 = ∠5 = 710.