Angle A is 2 times less than angle B; angle C is 50 ° greater than angle B. How many degrees are each

Angle A is 2 times less than angle B; angle C is 50 ° greater than angle B. How many degrees are each of these angles if their sum is 210 °?

Let the angle A be equal to x degrees, then the angle B is equal to 2x degrees, and the angle C is equal to (2x + 50) degrees. By the condition of the problem, it is known that the sum of these three angles A, B and C is equal to (x + 2x + (2x + 50)) degrees or 210 degrees. Let’s make an equation and solve it.

x + 2x + (2x + 50) = 210;

x + 2x + 2x + 50 = 210;

5x + 50 = 210;

5x = 210 – 50;

5x = 160;

x = 160: 5;

x = 32 ° – angle A;

2x = 32 * 2 = 64 ° – angle B;

2x + 50 = 64 + 50 = 114 ° – angle C.

Answer. ∠A = 32 °; ∠B = 64 °; ∠C = 114 °.