Angle A of the isosceles trapezoid ABCD is equal to 750. From point A, a straight line is drawn
March 2, 2021 | education
| Angle A of the isosceles trapezoid ABCD is equal to 750. From point A, a straight line is drawn that intersects the side BC at point K, and CD = CK. Find the corner CDK.
It is known that the sum of the angles of a trapezoid adjacent to the lateral side is 180 degrees.
Find the angle ABC:
angle ABC = angle BCD = 180 – 75 = 105 °;
Consider the triangle KCD.
It is isosceles because СK = CD, and the angle at its apex is 105 °.
The angles of a triangle add up to 180 °
Find the angle CDK:
(180 – 105) / 2 = 75/2 = 37.5 °
Answer: The CDK angle is 37.5 °.
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