Angle A of triangle ABC is twice its angle B. Angle C is three times less than angle B. Find the angles of the triangle.

Answer: angle A – 108 degrees, angle B – 54 degrees, angle C – 18 degrees
Solution:
1) the sum of the angles of the triangle is 180 degrees, that is, A + B + C = 180
2) according to the conditions of the problem, angle A is 2 times greater than angle B, which means A = 2 * B
3) according to the conditions of the problem, the angle C is 3 times less than the angle B, which means C = 1/3 * B
4) it turns out that 2B + B + 1 / 3B = 180, 3B + 1 / 3B = 180, B = 54 degrees
5) then the angle A is 54 * 2 = 108 degrees
6) thus the angle C is 54/3 = 18 (degrees)