Angle A of triangle ABC is twice its angle B. Angle C is three times smaller than angle B. Find the corners of the triangle.

Given triangle ABC. The smaller of the angles of this triangle is angle C, suppose that it has one part (1), angle C is three times less than angle B, so there are three parts to angle B (3), angle A of triangle ABC is twice as large its angle B, so it has six parts (3 * 2). It is necessary to find the corners of the triangle.

The sum of the angles of the triangle is 180 °, that is, A + B + C = 180 °, which means

3 * 2 + 3 + 1 = 10 parts in 180;
180 °: 10 = 18 ° angle C;
18о * 3 = 54 value of the angle B;
54о * 2 = 108 value of the angle A.
Answer: 108o, 54o, 18o.