Angle B of triangle ABC is 2 times less than angle A and 20 degrees more than angle C. Find the angles of the triangle.

1) Let us find out how many degrees the angle A is, if it is known that it is 2 times greater than the angle B and 20 degrees less than the angle C. We make an equation where:

X – angle B;

2X – angle A;

X – 20 – corner C.

180 is the common degree of the angles of the triangle.

X + 2X + X – 20 = 180;

4X = 180 + 20;

4X = 200;

X = 200/4;

X = 50 °.

2) Find out the degree of angle A if it is 2 times greater than angle B.

50 * 2 = 100 °

3) Find angle C if it is 20 ° less than angle B.

50 – 20 = 30 °.

Answer: the angles of the triangle ABC are equal, the angle A = 100 °, B = 50 °, C = 30 °.