Angle C = 90 degrees, AB = 3 CB = 3 find sin B.
| April 25, 2021 | education
Since the angle is C = 90, triangle ABC is right-angled with hypotenuse AB. By the Pythagorean theorem, we get:
AB ^ 2 = AB ^ 2 + CB ^ 2 = 3 ^ 2 + 3 ^ 2 = 2 * 3 ^ 2.
Then:
AB = √2 * 3 ^ 2 = 3√2.
According to the definition of the sine of an angle, the equality is true:
sin (B) = AC / AB = 3 / 3√2 = 1 / √2.
Answer: the value of the desired sine is 1 / √2 (angle B is 45).
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