Angles A and D at the base of trapezoid ABCD are 70 and 50. Calculate the degree measures of its remaining angles.

By the property of a trapezoid, the sum of the angles at the lateral sides of the trapezoid is 180.

Then the angle ABC + BAD = 180.

ABC = 180 – BAD = 180 – 70 = 110.

Angle ВСD + АDC = 180.

BCD = 180 – ADC = 180 – 50 = 130.

Answer: Angle ABC = 110, angle BCD = 130.



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