Angles A and D at the base of trapezoid ABCD are 72 ° and 86 °. Find a thermometer to measure the rest of its angles.

The two corners of the trapezoid adjacent to one side of the trapezoid are internal one-sided and, therefore, their sum is 180 °.

So, angle B is internal one-sided for angle A and, therefore:

∠В = 180 ° – ∠А = 180 ° – 72 ° = 108 °.

Angle C is internal one-sided for angle D and therefore:

∠С = 180 ° – ∠D = 180 ° – 86 ° = 94 °.

Answer: ∠В = 108 °; ∠С = 94 °.



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